Newsgroups: sci.math From: haoyuep@aol.com (Dan Hoey) Date: Jan 31, 2000 11:48 PM Subject: Re: geometric dissection problem with rectangles [ Reposted to sci.math--the original went only to rec.puzzles. ] David Bernier writes: >...The general question relates to two rectangles with integral >sides whose areas differ by one square unit; suppose a,b,c and d >are positive integers and that axb = cxd -1; suppose R_1 is an >axb rectangle and R_2 is a cxd rectangle; when can we dissect >R_1 into two pieces along grid lines which, when reassembled, >give R_2 less a hole of size 1x1 ? ... >As a specific instance, what about the case: a=13, b=8, c=21, d=5 ? This case is not possible. For suppose we have a rectangle A consisting of 13 rows of 8 squares. We wish to cut this to cover a shape B consisting of a 21 x 5 rectangle minus one square. Neither piece of A can be longer than 13 squares in any dimension. B must have at least one square on its first row and one square on its 21st row, and these must be covered by separate pieces of A because of the length restriction. The restriction also implies that no part of the top 8 rows of B can be covered by the piece that covers the 21st row, and since there are only two pieces, this 8 x 5 rectangle (minus at most one square) must be covered by one piece of A. Similarly, the bottom 8 rows of B form an 8 x 5 rectangle, minus at most one square, covered by the other piece of A. There are only two ways to cut the two 8 x 5 rectangles from A (even allowing a one-square overcut), and in neither case is any of the unused part of A contained in the oo x 5 strips formed by extending the 8x5 rectangles' long axis. So there is no way to extend the pieces to cover the central 5 rows of B, QED. This is a fairly ad hoc way of deciding a two-piece dissection problem, but it is good enough to show that no skip-2-Fibonacci rectangle (of size F_(n+1) x F_(n-2)) can be cut in two sets of squares to cover the corresponding adjacent-Fibonacci rectangle (F_n x F_(n-1)) minus one square, for F_n > 5. ObPuzzle: Find the part of the proof violated by F_n=5. Dan Hoey